Javascript:표 정렬 - 편집 역사

Sam: 새 문서: {{Javascript}} == 개요 == 표의 내용에 따라 오름차순, 내림차순의 정렬.
= 정렬 스크립트 = https://www.w3schools.com/howto/howto_js_sort_table.asp
2022-11-21T08:50:56Z

새 문서: {{Javascript}} == 개요 == 표의 내용에 따라 오름차순, 내림차순의 정렬. <br /> = 정렬 스크립트 = https://www.w3schools.com/howto/howto_js_sort_table.asp<nowi...

새 문서
{{Javascript}}

== 개요 ==
표의 내용에 따라 오름차순, 내림차순의 정렬.
<br />

= 정렬 스크립트 =
https://www.w3schools.com/howto/howto_js_sort_table.asp<nowiki/>의 코드를 참고하였다.

취향에 따라 구현 방법은 다르겠지만.. 테이블 태그 안에서 함수를 호출하여 사용하자.<syntaxhighlight lang="html">
<table class="table table-hover sortable" id="jb-table">
<thead class="table-dark">
<tr>
<th onclick="sortTable(0)">문항</th>
<th onclick="sortTable_int(1)">점수</th>
</syntaxhighlight>

=== 일반 텍스트 ===
<syntaxhighlight lang="javascript">
<script>
function sortTable(n) {
var table, rows, switching, i, x, y, shouldSwitch, dir, switchcount = 0;
table = document.getElementById("jb-table");
switching = true;
// Set the sorting direction to ascending:
dir = "asc";
/* Make a loop that will continue until
no switching has been done: /
while (switching) {
// Start by saying: no switching is done:
switching = false;
rows = table.rows;
/ Loop through all table rows (except the
first, which contains table headers): /
// i값으로 몇행부터 정렬 할지 정한다.
for (i = 3; i < (rows.length - 1); i++) {
// Start by saying there should be no switching:
shouldSwitch = false;
/ Get the two elements you want to compare,
one from current row and one from the next: /
x = rows[i].getElementsByTagName("TD")[n];
y = rows[i + 1].getElementsByTagName("TD")[n];
/ Check if the two rows should switch place,
based on the direction, asc or desc: /
if (dir == "asc") {
if (x.innerHTML.toLowerCase() > y.innerHTML.toLowerCase()) {
// If so, mark as a switch and break the loop:
shouldSwitch = true;
break;
}
} else if (dir == "desc") {
if (x.innerHTML.toLowerCase() < y.innerHTML.toLowerCase()) {
// If so, mark as a switch and break the loop:
shouldSwitch = true;
break;
}
}
}
if (shouldSwitch) {
/ If a switch has been marked, make the switch
and mark that a switch has been done: /
rows[i].parentNode.insertBefore(rows[i + 1], rows[i]);
switching = true;
// Each time a switch is done, increase this count by 1:
switchcount ++;
} else {
/ If no switching has been done AND the direction is "asc",
set the direction to "desc" and run the while loop again. /
if (switchcount == 0 && dir == "asc") {
dir = "desc";
switching = true;
}
}
}
}
</script>
</syntaxhighlight>

=== 숫자 ===
11, 5 등의 숫자데이터는 자바스크립트에서 자료형을 바꿔주지 않으면 텍스트로 처리하여 정렬해 오름차순에서 11보다 5가 큰 것으로 인식한다.<syntaxhighlight lang="javascript">
<script>
function sortTable_int(n) {
var table, rows, switching, i, x, y, shouldSwitch, dir, switchcount = 0;
table = document.getElementById("jb-table");
switching = true;
// Set the sorting direction to ascending:
dir = "asc";
/ Make a loop that will continue until
no switching has been done: /
while (switching) {
// Start by saying: no switching is done:
switching = false;
rows = table.rows;
/ Loop through all table rows (except the
first, which contains table headers): /
// i값으로 몇행부터 할지 정한다.
for (i = 3; i < (rows.length - 1); i++) {
// Start by saying there should be no switching:
shouldSwitch = false;
/ Get the two elements you want to compare,
one from current row and one from the next: /
x = rows[i].getElementsByTagName("TD")[n];
y = rows[i + 1].getElementsByTagName("TD")[n];
x = parseInt(x.innerHTML)
y = parseInt(y.innerHTML)
/ Check if the two rows should switch place,
based on the direction, asc or desc: /
if (dir == "asc") {
if (x > y) {
// If so, mark as a switch and break the loop:
shouldSwitch = true;
break;
}
} else if (dir == "desc") {
if (x < y) {
// If so, mark as a switch and break the loop:
shouldSwitch = true;
break;
}
}
}
// 행을 바꾸는 동작.
if (shouldSwitch) {
/ If a switch has been marked, make the switch
and mark that a switch has been done: /
rows[i].parentNode.insertBefore(rows[i + 1], rows[i]);
switching = true;
// Each time a switch is done, increase this count by 1:
switchcount ++;
} else {
/ If no switching has been done AND the direction is "asc",
set the direction to "desc" and run the while loop again. */
if (switchcount == 0 && dir == "asc") {
dir = "desc";
switching = true;
}
}
}
}
</script>
</syntaxhighlight>